Question

A triangle ABC with AB = 6 cm, $\angle A={30}^{\circ }$ and $\angle B={60}^{\circ }$ is given. The image of construction of $\Delta A{B}^{\prime }{C}^{\prime }$ similar to $\Delta ABC$ with base $A{B}^{\prime }=8cm$ is given below.


The postulate used for drawing B'C' || BC is:

• A. Corresponding angles are equal
• B. Alternate interior angles are equal
• C. Co-interior angles are supplementary
• D. Perpendicular bisector theorem

Answer 1

The correct option is A Corresponding angles are equal

Since, we know the length of $A{B}^{\prime }=8cm$, we can draw B'C' parallel to BC by using corresponding angles$(\angle CBA=\angle C^{\prime }{B}^{\prime }A)$.