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Constructions of Triangles

A triangle AB...

Question

A triangle ABC with sides BC = 7 cm, ∠B = 45°, ∠A = 105° is given. The image of constructing a similar triangle of ABC whose sides are 3/4 times the corresponding sides of the triangle ABC is given below. Then (A′ C′)/AC is equal to:

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Solution

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Similar questions

△ A B C

B C = 7 c m

∠ B = 45^{\circ}, ∠ A = 105^{\circ}

\frac{4}{3}

△ A B C

∠ B = 45^{\circ}, ∠ A = 105^{\circ}

Δ A B C

\frac{3}{4}

Δ A B C

\frac{A^{'} C^{'}}{A C}

A B C

B C = 6 c m, A B = 5 c m

∠ A B C = 60^{\circ}

Δ A B C

\frac{3}{4}

Δ A B C

∠ C B X

∠ B = 45^{\circ}, ∠ A = 105^{\circ}

Δ A B C

\frac{3}{4}

Δ A B C

∠

45^{\circ}

∠

105^{\circ}

\frac{4}{3}

Δ

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