A triangle ABC with sides BC -7cm- - B -45- - A -105- is given- The image of constructing a similar triangle of - ABC whose sides are 3-4 times the corresponding sides of the - ABC is given below-The condition used to draw A-C- parallel to AC-

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Byju's Answer

Standard IX

Mathematics

Construction of Triangle 2

A triangle AB...

Question

A triangle ABC with sides BC =7cm, $∠ B = 45^{\circ}, ∠ A = 105^{\circ}$ is given. The image of constructing a similar triangle of $Δ A B C$ whose sides are $\frac{3}{4}$ times the corresponding sides of the $Δ A B C$ is given below.

The condition used to draw A'C' parallel to AC:

Corresponding angles are equal

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Alternate interior angles are equal

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Co-interior angles are supplementary

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Perpendicular bisector theorem

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Solution

The correct option is A Corresponding angles are equal

Here we use the principle that when corresponding angles are equal, the lines are parallel.
$∠ A^{'} C^{'} B = ∠ A C B \to$ AC||A'C'.

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Similar questions

Q. A triangle ABC with sides BC =7cm,

∠ B = 45^{\circ}, ∠ A = 105^{\circ}

is given. The image of constructing a similar triangle of

Δ A B C

whose sides are

\frac{3}{4}

times the corresponding sides of the

Δ A B C

is given below.

The condition used to draw A'C' parallel to AC:

Q. A triangle ABC with sides BC =7cm,

∠ B = 45^{\circ}, ∠ A = 105^{\circ}

is given. The image of constructing a similar triangle of

Δ A B C

whose sides are

\frac{3}{4}

times the corresponding sides of the

Δ A B C

is given below. Then

\frac{A^{'} C^{'}}{A C}

is equal to :

Draw a triangle ABC with side BC = 7 cm, ∠B = 45°, ∠A = 105°. Then, construct a triangle whose sides are times the corresponding side of ΔABC. Give the justification of the construction.

Q. A triangle

A B C

with

B C = 6 c m, A B = 5 c m

and

∠ A B C = 60^{\circ}

The image of constructing a similar triangle of

Δ A B C

whose sides are

\frac{3}{4}

times the corresponding sides of the

Δ A B C

is given below.

∠ C B X

is a/an :

Question 6
Draw a triangle ABC with side $B C = 7 c m, ∠ B = 45^{\circ}, ∠ A = 105^{\circ}$ . Then, construct a triangle whose sides are 4/3 times the corresponding sides of $Δ A B C$ .

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A triangle ABC with sides BC =7cm, ∠B=45∘,∠A=105∘ is given. The image of constructing a similar triangle of ΔABC whose sides are 34 times the corresponding sides of the ΔABC is given below. The condition used to draw A'C' parallel to AC:

The correct option is A Corresponding angles are equal Here we use the principle that when corresponding angles are equal, the lines are parallel. ∠A′C′B=∠ACB→ AC||A'C'.

A triangle ABC with sides BC =7cm, $∠ B = 45^{\circ}, ∠ A = 105^{\circ}$ is given. The image of constructing a similar triangle of $Δ A B C$ whose sides are $\frac{3}{4}$ times the corresponding sides of the $Δ A B C$ is given below.

The condition used to draw A'C' parallel to AC:

The correct option is A Corresponding angles are equal

Here we use the principle that when corresponding angles are equal, the lines are parallel.
$∠ A^{'} C^{'} B = ∠ A C B \to$ AC||A'C'.