A triangle $A B C$ with vertices $A (- 1, 0), B (- 2, 3 / 4), a n d C (- 1, 2)$ has its orthocentre $H$ . Then the orthocenter of triangle $B C H$ will be:

(- 3, - 2)

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(1, 3)

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(- 1, 0)

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None of these

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Solution

The correct option is C $(- 1, 0)$
Orthocenter of BCH = verten of A $= (- 1, 0)$

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