Question

A triangle and a parallelogram are constructed on the same base such that their areas are equal. If the altitude of the parallelogram is $100m$, then the altitude of the triangle is:

• A. $100m$
• B. $200m$
• C. $100\sqrt{2}$ m
• D. $10\sqrt{2}$ m

Answer 1

The correct option is B $200m$

Let the altitude of the $\Delta =h_1$ and altitude of the parallelogram $=h_2$

Let base of both $\Delta$ and parallelogram$=b$
Then, $b\times h_2=\frac{1}{2}\times b\times h_1$
$\Rightarrow h_1=2h_2$

$\Rightarrow h_1=2\times 100m=200m$