Question

A triangle $\Delta$ PQR with $\angle Q={90}^{\circ }$, QR = 8 cm and PR = 10 cm is constructed. What would be the measure of PQ?

• A. 3 cm
• B. 4 cm
• C. 10 cm
• D. 6 cm

Answer 1

The correct option is D 6 cm

Given $\angle Q={90}^{\circ }$, which means that the sides PQ and QR are the sides and PR is the hypotenuse of the right angle triangle. Using Pythagoras theorem, we get
$P{R}^2=P{Q}^2+Q{R}^2$
$\Rightarrow {10}^2=P{Q}^2+8^2$
$\Rightarrow P{Q}^2={10}^2-8^2$
$\Rightarrow P{Q}^2=100-64$
$\Rightarrow P{Q}^2=36$
$\Rightarrow PQ=6$