A triangle has its vertices on a rectangular hyperbola, then the orthocentre of the triangle lies on the :
A
parabola
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B
same hyperbola
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C
another hyperbola
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D
director circle
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Solution
The correct option is C same hyperbola let the vertices of the triangle be (c/t1,ct1), (c/t2,ct2), (c/t3,ct3) Then its orthocenter is (−ct1t2t3,−ct1t2t3) Therefore, it lies on the same curve xy=c2