Question

A triangle has sides of 48 cm, 14 cm and 50 cm. Find its circum-radius.

Answer 1

${48}^2=2304$

${14}^2=196$

${50}^2=2500$

${48}^2+{14}^2={50}^2$

Therefore, the triangle is right angled and its hypotenuse is 50 cm.

Its circum-radius = $\frac{50}{2}=25$ $cm$