A triangle has vertices at $(6, 7), (2, - 9)$ and $(- 4, 1)$ . Find the slope of its sides.

\frac{11}{7}, - 13, - \frac{1}{4}

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\frac{11}{7}, 13, - \frac{1}{4}

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\frac{11}{7}, - 13, \frac{1}{4}

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None of these

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Solution

The correct option is D None of these
Given the points $A (6, 7)$ , $B (2, - 9)$ , and $C (- 4, 1)$ .

Slope of an line is given by formula $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

So,

slope of side $A B = m_{1} = \frac{y_{b} - y_{a}}{x_{b} - x_{a}} = \frac{- 9 - 7}{2 - 6} = 4$ .

Similarly slope of $B C = m_{2} = \frac{y_{c} - y_{b}}{x_{c} - x_{b}} = - \frac{5}{3}$ and

slope of side $C A = m_{3} = \frac{y_{a} - y_{c}}{x_{a} - x_{c}} = \frac{7 - 1}{6 + 4} = \frac{3}{5}$

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Similar questions

Q. If U = {1, 3, 5, 7, 9, 11, 13}, then which of the following are subsets of U.
B = {2, 4}
A = {0}
C = {1, 9, 5, 13}
D = {5, 11, 1}
E = {13, 7, 9, 11, 5, 3, 1}
F = {2, 3, 4, 5}

Q. Find the sum

\frac{1}{5 \times 7} + \frac{1}{7 \times 9} + \frac{1}{9 \times 11} + \frac{1}{11 \times 13} + \frac{1}{13 \times 15}

Multiplicative inverse of

1) -7/9

2) 13/15

3) 1/3×4/7

4) -13/11×1/5

Question 13.
$\frac{11}{7}$ can be expressed in the form
(a) 7 $\frac{1}{4}$
(b) 4 $\frac{1}{7}$
(c) 1 $\frac{4}{7}$
(d) 11 $\frac{1}{7}$

$(i) \frac{3}{7} + \frac{- 4}{9} - \frac{- 11}{7} - \frac{7}{9} (i i) \frac{2}{3} + \frac{- 4}{5} - \frac{1}{3} - \frac{2}{5} (i i i) \frac{4}{7} - \frac{- 8}{9} - \frac{- 13}{7} + \frac{17}{9}$

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A triangle has vertices at (6,7),(2,−9) and (−4,1). Find the slope of its sides.

The correct option is D None of theseGiven the points A(6,7), B(2,−9), and C(−4,1).Slope of an line is given by formula m=y2−y1x2−x1So,slope of side AB=m1=yb−yaxb−xa=−9−72−6=4.Similarly slope of BC=m2=yc−ybxc−xb=−53 andslope of side CA=m3=ya−ycxa−xc=7−16+4=35

A triangle has vertices at $(6, 7), (2, - 9)$ and $(- 4, 1)$ . Find the slope of its sides.