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Question

A triangle is drawn by joining a point on the semi-circle to the ends of the diameter. Two semi-circles are drawn with the other two sides as diameter.

Find the sum of the areas of shaded part.


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Solution

Let AB=a, AC=b

BC = a2+b2 (Δ ABC is a right triangle)

ΔBAC=90 (angle in semi-circle)

Now, area of Δ ABC = 12ab

Now, area of semi-circle as diameter AB = 12π(a2)2

and , area of semi-circle as diameter AC = 12π(b2)2

area of semi-circle as diameter BC =12π[a2+b22]2

Now, area of shaded part

= [12πa24+12πb24][12π(b2+a24)12ab]

=π8(a2+b2)π8(a2+b2)+12ab

= 12ab = 12(AB)(BC)


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