A triangle is formed by the coordinates $(0, 0)$ , $(0, 21)$ and $(3, 0)$ . Find the number of integral coordinates which are strictly lies inside triangle (integral co- ordinates has both $x$ and $y$ as integers):

19

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20

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21

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38

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Solution

The correct option is A $19$
The equation of AB is
$y - 0 = \frac{- 21}{3} (x - 3)$
$y + 7 x = 21$
For strictly inside, we have to avoid points which are on triangle
So, number of point which are in triangle having integral
x & y coordinate $= 13 + 6$ $= 19$

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A triangle is formed by the coordinates (0,0), (0,21) and (3,0). Find the number of integral coordinates which are strictly lies inside triangle (integral co- ordinates has both x and y as integers):

The correct option is A 19The equation of AB isy−0=−213(x−3)y+7x=21For strictly inside, we have to avoid points which are on triangleSo, number of point which are in triangle having integral x & y coordinate =13+6 =19

A triangle is formed by the coordinates $(0, 0)$ , $(0, 21)$ and $(3, 0)$ . Find the number of integral coordinates which are strictly lies inside triangle (integral co- ordinates has both $x$ and $y$ as integers):

The correct option is A $19$
The equation of AB is
$y - 0 = \frac{- 21}{3} (x - 3)$
$y + 7 x = 21$
For strictly inside, we have to avoid points which are on triangle
So, number of point which are in triangle having integral
x & y coordinate $= 13 + 6$ $= 19$