Question

A triangle of area $9y$ $c{m}^2$ has been drawn such that its area is equal to the area of an equilateral triangle of side $6cm$. Then, the value of $y$ is

• A. $\sqrt{2}$ $cm$
• B. $\sqrt{3}$ $cm$
• C. $2cm$
• D. $3cm$

Answer 1

Answer: (B)

$\sqrt{3}$ $cm$

Area of an equilateral triangle with length of side $a=\frac{\sqrt{3}}{4}{a}^2$
Given, area of the equilateral triangle $=9y{cm}^2$
$\therefore \frac{\sqrt{3}}{4}{6}^2=9y$
$\therefore y=\sqrt{3}cm$