Question

A triangle of area $9\times yc{m}^2$ has been drawn such that its area is equal to the area of an equilateral triangle of side 6 cm. Then the value of y is

• A. $\sqrt{2}cm$
• B. $\sqrt{3}cm$
• C. $2$ cm
• D. $3$ cm

Answer 1

The correct option is B $\sqrt{3}cm$

Area
of an equilateral triangle with length of side $a=\frac{\sqrt{3}}{4}{a}^2=\frac{\sqrt{3}}{4}{6}^2=9\sqrt{3}{cm}^2$
Given, $9\times y=9\sqrt{3}$
$=>y=\sqrt{3}cm$