A triangular corner is cut from a rectangular piece of paper and the resulting pentagon has sides $5, 6, 8, 9, 12$ in some order. The ratio of the area of the pentagon and the area of the rectangle is:

\frac{11}{18}

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\frac{13}{18}

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\frac{15}{18}

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\frac{17}{18}

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Solution

The correct option is C $\frac{17}{18}$
Angle of Rectangle $= 12 \times 9$
Area of pentagon $= 12 \times 9 - \frac{1}{2} \times 3 \times 4$
$= 12 \times 9 - 6$
$R e q u i r e d = \frac{12 \times 9 - 6}{12 \times 9} = \frac{17}{18}$ .

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A triangular corner is cut from a rectangular piece of paper and the resulting pentagon has sides 5,6,8,9,12 in some order. The ratio of the area of the pentagon and the area of the rectangle is:

The correct option is C 1718Angle of Rectangle =12×9Area of pentagon =12×9−12×3×4=12×9−6Required=12×9−612×9=1718.

A triangular corner is cut from a rectangular piece of paper and the resulting pentagon has sides $5, 6, 8, 9, 12$ in some order. The ratio of the area of the pentagon and the area of the rectangle is:

The correct option is C $\frac{17}{18}$
Angle of Rectangle $= 12 \times 9$
Area of pentagon $= 12 \times 9 - \frac{1}{2} \times 3 \times 4$
$= 12 \times 9 - 6$
$R e q u i r e d = \frac{12 \times 9 - 6}{12 \times 9} = \frac{17}{18}$ .