A triangular pipe network is shown in the figure
The head loss in each pipe is given by hf =r.Q1.8 with the variables expressed in a consistent set of units. The value of r for the pipe AB is 1 and for the pipe BC is 2. If the discharge supplied at the point A (i.e., 100) is equally divided between the pipes AB and AC, the value of r (up to 2 decimal places) for the pipe AC should be
Given
hf =r.Q1.8
Because of the given condition of equal discharge distribution in pipe AB & AC, the discharge in AB and AC will be 50 and 50. Now satisfy continuity at point B and C
For close Loop ABCA
∑hr=0
⇒ 1(50)1.8−2(20)1.8−r(50)1.8=0
⇒ 1143.26−439.42=r(50)1.8
r=0.62