A triangular set square of angles $30^{\circ}, 60^{\circ}, 90^{\circ}$ and if negligible mass is suspended freely from the right angled corner and weights are hung at the two corners. If the hypotenuse of the set square sets horizontally, then the ratio of the weights $W_{1} / W_{2}$ is:-

1 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{3} : 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1 : \sqrt{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\sqrt{3} : 1$
As the hyptonuse of the set equare remains horizontal therfore, net torque cting on it becomes $z e r o$
So,
$\frac{x}{l_{1}} = t a n 30^{0} \Rightarrow l_{1} = \frac{x}{t a n 30} = \sqrt{3} x$
Similarly,
$\frac{x}{l_{2}} = t a n 60^{0} \Rightarrow l_{2} = \frac{x}{t a n 60} = \frac{x}{\sqrt{3}}$
thus,
$W_{1} L_{1} = W_{2} L_{2}$
$\frac{W_{1}}{W_{2}} = \frac{x}{\sqrt{3} \times \sqrt{3} x}$
$\frac{W_{1}}{W_{1}} = \frac{1}{3}$
$h e n c e, W_{1} : W_{2} = 1 : 3$

Suggest Corrections

Similar questions

Q. A triangular set square of angle

30^{\circ}, 60^{\circ}

and

90^{\circ}

and of negligible mass is suspended freely from the right-angle corner and weights are hung at the two corners. If the hypotenuse of the set square adjust horizontally, then the ratio of the weights

\frac{W_{1}}{W_{2}}

1 : n

. The value of n is (integer only)

Q. A

30^{\circ}, 60^{\circ}

triangular set square of negligible mass is suspended freely from the right angled corner and weights are hung at the two corners as shown in figure. The ratio of masses,

\frac{m_{1}}{m_{2}}

of the weights, if the hypotenuse of the set square sets horizontally, is

As both the set-squares have right angle at one corner, the set-square that is the isosceles triangle has two angles measuring ______ each and the set square that is the scalene triangle has two angles measuring ______and ______.

The side of right angle triangle containing right angle is 5x and (3x-1 ) cm. Calculate the length of the hypotenuse of the triangle if it's area is 60cm square.

Q. Let

A (h, k), B (1, 1)

and

C (2, 1)

be the vertices of a right angled triangle with

A C

as its hypotenuse. If the area of the triangle is 1 square unit, then the set of values which

^{'} k^{'}

can take is given by

Join BYJU'S Learning Program

A triangular set square of angles 30∘,60∘,90∘ and if negligible mass is suspended freely from the right angled corner and weights are hung at the two corners. If the hypotenuse of the set square sets horizontally, then the ratio of the weights W1/W2 is:-

The correct option is C √3:1As the hyptonuse of the set equare remains horizontal therfore, net torque cting on it becomes zeroSo, xl1=tan300⇒l1=xtan30=√3xSimilarly,xl2=tan600⇒l2=xtan60=x√3thus,W1L1=W2L2W1W2=x√3×√3xW1W1=13hence,W1:W2=1:3

A triangular set square of angles $30^{\circ}, 60^{\circ}, 90^{\circ}$ and if negligible mass is suspended freely from the right angled corner and weights are hung at the two corners. If the hypotenuse of the set square sets horizontally, then the ratio of the weights $W_{1} / W_{2}$ is:-