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A triangular ...

Question

A triangular table whose sides are in a ratio $3 : 4 : 5$ and perimeter is $36$ m, then find the area of the table

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Solution

Given sides ratio is $3 : 4 : 5$
Let the sides are $3 x, 4 x, 5 x$
Perimeter $= 2 s = 36 ⟹ 3 x + 4 x + 5 x = 36 ⟹ x = 3$
$s = 18$
Area $= \sqrt{18 (18 - 9) (18 - 12) (18 - 15)} = 54$

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