Question

A trihybrid cross is made between two plants with genotypes A/a B/b C/c, how many offsprings of such cross will have a genotype a/a b/b c/c?

• A. 1/64
• B. 1/4
• C. 1/16
• D. 1/32

Answer 1

Answer: (A)

1/64

If we consider a cross between AaBbCc, the value of n = 3.
The maximum number of possible gametes is 2 raised to 'n'.
Value of n = 3.
Thus, maximum 2x2x2 = 8 gametes are produced. This makes it clear that maximum offspring produced is 8x8 = 64. The possibility of a recessive genotype in this combination of Punnet square is 1/64. This means that one out of 64 offspring produced will have aabbcc genotype.