Question

A triode valve operates at $V_p=225V$ and $V_R$ = -0.5 V.
The plate current remains unchanged if the plate voltage is increased to 250 V and the grid voltage is decreased to - 2.5 V calculate the amplifiation factor.

Answer 1

Amplification factor for Triode Valve
$\mu =\frac{\text{Charge in plate voltage}}{\text{Charge in grid voltage}}=\frac{\delta V_p}{\delta V_g}=\frac{250-225}{2.5-0.5}=\frac{25}{2}=12.5$ $$\left[\begin{array}{c}\therefore \delta V_p=250-225\\ \delta V_g=2.5-0.5\end{array}\right]$$