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Standard XII

Physics

Pseudo Force

A trolley 100...

Question

A trolley ( $100 kg$ ) moving forward with acceleration of $1 {m/s}^{2}$ has block of $1 kg$ mass present on its floor. Find pseudo force acting on block $^{'} A^{'}$ with respect to a reference frame attached to trolley

- 1 N

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1 N

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100 N

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10 N

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Solution

The correct option is A $- 1 N$
We know that
$\Rightarrow$ Pseudo force = $- m a$
here $m$ is mass of body
$a$ is acceleration of noninertial frame
$F_{p} = (mass of body) \times - (acceleration of frame)$
$= - 1 \times 1 = - 1 N$

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A trolley (100 kg) moving forward with acceleration of 1 m/s2 has block of 1 kg mass present on its floor. Find pseudo force acting on block ′A′ with respect to a reference frame attached to trolley

The correct option is A −1 NWe know that ⇒ Pseudo force = −ma here m is mass of body a is acceleration of noninertial frame Fp=(mass of body)×−(acceleration of frame) =−1×1=−1 N

A trolley ( $100 kg$ ) moving forward with acceleration of $1 {m/s}^{2}$ has block of $1 kg$ mass present on its floor. Find pseudo force acting on block $^{'} A^{'}$ with respect to a reference frame attached to trolley

The correct option is A $- 1 N$
We know that
$\Rightarrow$ Pseudo force = $- m a$
here $m$ is mass of body
$a$ is acceleration of noninertial frame
$F_{p} = (mass of body) \times - (acceleration of frame)$
$= - 1 \times 1 = - 1 N$