A trolley car slides down a smooth inclined plane of angle of inclination θ. If a body is suspended from the roof of the trolley car by an inextensible string of length l, the corresponding tension in the string will be
A
mg
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B
mg cosθ
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C
mg sinθ
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D
None of these
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Solution
The correct option is B mg cosθ
Let tension in string be ′T′ and block of mass m be sliding down an inclined plane with an angle of inclination θ . Since acceleration is along the plane, applying condition of equilibrium perpendicular to plane, T−mgcosθ=0 T=mgcosθ