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Question

A trolley carries a body of weight 25 kg. which is kept at a distance of 2.5 m from the rear end of the trolley. The trolley starts from rest and accelerates at a constant rate of 2 ms2 If the coefficient of friction between the trolley and the body is 0.1, find the distance of the trolley from the starting point where the body will just slip out of the trolley. Take g=10ms2

A
4 m
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B
3 m
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C
5 m
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D
10 m
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Solution

The correct option is C 5 m
The force which moves the body is the frictional force.
fmax=μ mgamax=μ g=0.1×10
=1 ms2<2 ms2
slipping
Relative acceleration =21=1 ms2
2.5=0×t+12×1×t2t2=5t=5 s
Distance travelled by the trolley in this time s=ut+12at2=0+12×2×5=5 m

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