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Question

A trolley of mass m is connected to two identical springs, each of force constant k, as shown in figure. The trolley is displaced from its equilibrium position by a distance x and released. The trolley executes simple harmonic motion of period T. After some time it comes to rest due to friction. The total energy dissipated as heat is (assume the damping force to be weak)

A
12kx2
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B
kx2
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C
2π2mx2r2
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D
mx2r2
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Solution

The correct option is B kx2
In general, the motion of a damped oscillator is not simple harmonic. If the damping forces are weak, the motion is very nearly simple harmonic and all formulae of SHM apply. The amplitude A = x. The time period T is T=2πm2k ..........(i) If the trolley eventually comes to rest, the entire energy of oscillation is dissipated as heat due to friction. Hence, the total energy dissipated as heat is
E=12mA2ω2=12mA2(2πr)2=2π2mA2r2E=12mA2ω2=12mx2(2πr)2=2π2mx2r2
(ii) Which is choice (c).
Using (i) in (ii) we get E=kx2
Hence choice (b) is also correct.


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