Question

A trolley, while going down an inclined plane, has an acceleration of 2 cm s⁻². What will be its velocity 3 s after the start?

Answer 1

Initial velocity of the trolley, u = 0 (since the trolley was initially at rest)

Acceleration, a = 2 cm s⁻² = 0.02 m/s²

Time, t = 3 s

According to the first equation of motion:

v = u + at

Where, v is the velocity of the trolley after 3 s from start

v = 0 + 0.02 × 3 = 0.06 m/s

Hence, the velocity of the trolley after 3 s from start is 0.06 m/s.