Question

A trolley, while going down an inclined plane, has an acceleration of $2cm{s}^{-2}$. What will be its velocity $3s$ after the start?

Answer 1

Step 1: Given

Acceleration $a=2cm{s}^{-2}=0.02m{s}^{-2}$

Time, $t=3s$

Initial velocity, $u=0m{s}^{-1}$

Final velocity, $v$

Step 2: Formula used

$v=u+at$

Step 3: Calculation of velocity

Using the first equation of motion

$$\begin{gathered} v=u+at \\ \Rightarrow v=0+0.02m{s}^{-2}\times 3s \\ \Rightarrow v=0.06m{s}^{-1} \end{gathered}$$

Hence, the velocity of the trolley after $3s$ is $0.06m{s}^{-1}$.