Question

A trolley, while going down an inclined plane, has an acceleration of $2cm{s}^{-2}$. What will be its velocity $3s$ after the start?

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Solution

Step 1: Given Acceleration $a=2cm{s}^{-2}=0.02m{s}^{-2}$Time, $t=3s$Initial velocity, $u=0m{s}^{-1}$Final velocity, $v$Step 2: Formula used$v=u+at$Step 3: Calculation of velocityUsing the first equation of motion$v=u+at\phantom{\rule{0ex}{0ex}}⇒v=0+0.02m{s}^{-2}×3s\phantom{\rule{0ex}{0ex}}⇒v=0.06m{s}^{-1}$Hence, the velocity of the trolley after $3s$ is $0.06m{s}^{-1}$.

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