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Question

A trolley, while going down an inclined plane, has an acceleration of 2cm/s2. What will be its velocity in 3s after the start?


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Solution

Step 1: Given:

Initialspeed(u)=0m/s,Acceleraton(a)=2cm/s2Time(t)=3s

Step 2:Formula used:

v=u+at[where,visfinalvelocity,uisinitialvelocity,aisaccelerationandtistime]

Step 3:Final solution:

v=u+atv=0+2×3v=6cm/s

Thus the velocity of a trolley after 3sis6cm/s


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