A truck carries a box of mass $m = 50 k g$ on its flat horizontal rough surface with coefficient of friction $μ = 0.3$ . It is crossing a circular track of radius $27 m$ , what is the maximum speed of the truck so that the box does not slide from the truck while moving on the circular path.

18 k m / h r

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None of these

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32.4 k m / h r

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36 k m / h r

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Solution

The correct option is C $32.4 k m / h r$
FORMULA USED: $v = \sqrt{μ r g}$

Given: $μ = 0.3, r = 27 m$

$v = \sqrt{0.3 \times 27 \times 10}$

$v = 9 m / s$

$= 32.4 k m / h r$

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Q. A truck is carry a box of mass

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. It is crossing a circular track of radius

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