A truck covers first $80 k m$ in $2 h o u r s$ , and the remaining $60 k m$ in the next $3 h o u r s$ . What is the average speed of the truck?

32 k m h^{- 1}

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34 k m h^{- 1}

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28 k m h^{- 1}

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36 k m h^{- 1}

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Solution

The correct option is C $28 k m h^{- 1}$
Given:
Total distance covered = $(80 + 60) k m$ = $140 k m$
Total time taken = $(2 + 3) h = 5 h$
We know that, $A v e r a g e S p e e d = \frac{T o t a l d i s t a n c e c o v e r e d}{T o t a l T i m e t a k e n}$

Hence, the average speed
$\Rightarrow$ $\frac{140 k m}{5 h} = 28 k m h^{- 1}$

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