A truck driver drives $20 k m$ down the road in 5 minutes. He then reverses and drives $12 k m$ back down the road in 3 minutes. What is his average velocity?

4 k m / m i n

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2 k m / m i n

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3 k m / m i n

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60 k m / h

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Solution

The correct option is D $60 k m / h$
Total distance covered $= 20 k m + 12 k m = 32 k m$
Displacement $= 20 - 12 = 8 k m$
Time taken $= 5 + 3 = 8$ minutes

Average velocity $= 1 k m / m i n = 60 k m / h$

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A truck driver drives 20 km down the road in 5 minutes. He then reverses and drives 12 km back down the road in 3 minutes. What is his average velocity?

The correct option is D 60 km/hTotal distance covered =20 km+12 km=32 km Displacement =20−12=8 km Time taken =5+3=8 minutes Average velocity =1 km/min=60 km/h

A truck driver drives $20 k m$ down the road in 5 minutes. He then reverses and drives $12 k m$ back down the road in 3 minutes. What is his average velocity?

The correct option is D $60 k m / h$
Total distance covered $= 20 k m + 12 k m = 32 k m$
Displacement $= 20 - 12 = 8 k m$
Time taken $= 5 + 3 = 8$ minutes

Average velocity $= 1 k m / m i n = 60 k m / h$