A truck driver drives 20km down the road in 5minutes . He then reverses and drive 12km back down the road in 3minutes. What is the average velocity?
A
1km/min
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2km/min
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3km/min
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4km/min
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A1km/min The truck motion can be represented as shown below. Let truck starts from A and reaches B which is 20km far and then reverse back to reach C by driving 12km. So, net displacement of the truck is ΔS=AC=20−12=8km And, total time taken Δt=5+3=8min So, average velocity is given as vavg=△S△t=88=1km/min