A truck driver drives $20 km$ down the road in $5 minutes$ . He then reverses and drive $12 km$ back down the road in $3 minutes$ . What is the average velocity?

1 km/min

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2 km/min

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3 km/min

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4 km/min

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Solution

The correct option is A $1 km/min$
The truck motion can be represented as shown below.
Let truck starts from $A$ and reaches $B$ which is $20 km$ far and then reverse back to reach $C$ by driving $12 km$ .
So, net displacement of the truck is $Δ S = A C = 20 - 12 = 8 km$
And, total time taken $Δ t = 5 + 3 = 8 min$
So, average velocity is given as
$v_{a v g} = \frac{△ S}{△ t} = \frac{8}{8} = 1 km/min$

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A truck driver drives 20 km down the road in 5 minutes . He then reverses and drive 12 km back down the road in 3 minutes. What is the average velocity?

A truck driver drives $20 km$ down the road in $5 minutes$ . He then reverses and drive $12 km$ back down the road in $3 minutes$ . What is the average velocity?