A truck has to cover a distance of 112 km in 14 hours. If it covers $\frac{3}{4}$ $^{t h}$ of the journey in $\frac{4}{7}$ $^{t h}$ of the time, then at what speed should the truck run to cover the remaining distance in the time left?

4.66kmph

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

7.14kmph

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5.33kmph

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5.67kmph

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.33 kmph

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
4.66kmph

Time left $= 14 - [\frac{4}{7} \times 14] = 6$ hours

Distance to be covered $= 112 - [\frac{3}{4} \times 112] = 28$ km

$∴$ Speed of the truck $= \frac{28}{6} = 4.66$ kmph

Suggest Corrections

Similar questions

A truck covers a distance of 376 km at a certain speed in 8 hours. How much time would a car take at an average speed which is 18 kmph more than that of the speed of the truck to cover a distance which is 14 km more than that travelled by truck ?

Q. A truck cover

224 k m

4 h o u r s

, the average speed of a bike is

\frac{1}{4} t h

the average speed of the truck how much distance will the bike cover in seven hours?.

Q. A truck covers a distance of 150 km at a certain average speed and then covers another 200 km at an average speed which is 20 km per hour more than the first speed. If the truck covers the total distance in 5 hours, find the first speed of the truck. [CBSE 2015]

Q. A person sets to cover a distance of 12 km in 45 minutes. If he covers 3/4 of the distance in 2/3 time, what should be his speed to cover the remaining distance in the remaining time?

A truck running at 75 kmph takes one hour to cover a distance. If the speed is reduced by 15 kmph then in how much time it will cover the distance?

Join BYJU'S Learning Program

A truck has to cover a distance of 112 km in 14 hours. If it covers 34th of the journey in 47th of the time, then at what speed should the truck run to cover the remaining distance in the time left?

The correct option is A 4.66kmph Time left =14−[47×14]=6 hours Distance to be covered =112−[34×112]=28km ∴ Speed of the truck =286=4.66 kmph

A truck has to cover a distance of 112 km in 14 hours. If it covers $\frac{3}{4}$ $^{t h}$ of the journey in $\frac{4}{7}$ $^{t h}$ of the time, then at what speed should the truck run to cover the remaining distance in the time left?

The correct option is A
4.66kmph

Time left $= 14 - [\frac{4}{7} \times 14] = 6$ hours

Distance to be covered $= 112 - [\frac{3}{4} \times 112] = 28$ km

$∴$ Speed of the truck $= \frac{28}{6} = 4.66$ kmph