A truck moving at 72 km/hr carries a steel girder which rests on its wooden floor.what is the time in which the truck can come to stop without the girder moving forward,the co-efficient of friction is 0.5

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Solution

we have :
v=at+v0
v=0 when a truck stops
a=-v0/t
F=ma
a=F/m=-m0.5g/m=9.8*0.5=-4.9m/s^2
100km/h=20.016m/s
-4.9=-20.016/t
t=4.0848s

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A truck moving at 72 km/hr carries a steel girder which rests on its wooden floor.what is the time in which the truck can come to stop without the girder moving forward,the co-efficient of friction is 0.5

we have : v=at+v0 v=0 when a truck stops a=-v0/t F=ma a=F/m=-m*0.5*g/m=9.8*0.5=-4.9m/s^2 100km/h=20.016m/s -4.9=-20.016/t t=4.0848s

we have :
v=at+v0
v=0 when a truck stops
a=-v0/t
F=ma
a=F/m=-m0.5g/m=9.8*0.5=-4.9m/s^2
100km/h=20.016m/s
-4.9=-20.016/t
t=4.0848s