Question

A truck of mass 1000 kg is pulling a trailer of mass 2000 kg frictional force on truck is 500 N and on trailer is 1000 N. The truck extra force of 6000 N. calculate:-
a) Acceleration of the truck and the trailer.
b) The tension in the connecting rope.

Answer 1

(A) . Let $a$ be acceleration of truck and the trailer

$Fnet=ma$

6000 - (500+1000) = (1000+2000)$a$

therefore

$a=\frac{4500}{3000}=1.5m/s^2$

(B) let T be the tension in the connected rope.

$T=2000a+1000$

$=3000+1000$

$=4000N$