A truck of mass 2000kg travelling at 4 m/s comes to rest in 2 s when it strikes a wall. Force exerted by the wall is
A
2kN
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B
1kN
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C
4kN
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D
8kN
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Solution
The correct option is C4kN Given: Mass of truck; m=2×103 kg time; t=2 s Initial velocity of truck; vi=4 m/s As truck comes to rest. ∴Final velocity of truck; vf=0 m/s We know, Impulse (J)=Ft=ΔP Ft=m(vf−vi) F(2)=2×103(0−(−4)) 2F=8×103 F=4×103N=4kN