The correct option is D 5×104N
Here truck has initial velocity of 0 m/sec and travelled a distance of 0.5 Km which is also equal to 500 m in 10 seconds.
s=ut+0.5at2
s=0×10+0.5×a×102
500=0.5×a×100
a=10m/s2
Truck has a mass of 5000 Kg
F=m×a
F=5000×10N
F=5×104N.
Hence force is 5×104N.