A truck of mass $m$ is moved under a force F. If the truck is then loaded with an object of mass equal to the mass of the truck and the driving force is halved, then the acceleration becomes:

Half

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One-third

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One-fourth

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One-eighth

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Solution

The correct option is A One-fourth
$F = m a$
According to the question, body of same mass is loaded.
Total Mass = $m + m = 2 m$
Force $= \frac{1}{2} F$
$F = m a$
$\Rightarrow \frac{1}{2} F = 2 m a$
$∴ a = \frac{F}{4 m}$
So, acceleration becomes 1/4 times

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A truck of mass Mis moved under a force F. If the truck is then loaded with an object equal to the mass of the truck and the driving force is halved then how does the acceleration change?

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A truck of mass m is moved under a force F. If the truck is then loaded with an object of mass equal to the mass of the truck and the driving force is halved, then the acceleration becomes:

The correct option is A One-fourthF=maAccording to the question, body of same mass is loaded.Total Mass = m+m=2mForce =12FF=ma⇒12F=2ma∴a=F4mSo, acceleration becomes 1/4 times

A truck of mass $m$ is moved under a force F. If the truck is then loaded with an object of mass equal to the mass of the truck and the driving force is halved, then the acceleration becomes:

The correct option is A One-fourth
$F = m a$
According to the question, body of same mass is loaded.
Total Mass = $m + m = 2 m$
Force $= \frac{1}{2} F$
$F = m a$
$\Rightarrow \frac{1}{2} F = 2 m a$
$∴ a = \frac{F}{4 m}$
So, acceleration becomes 1/4 times