A truck running along a straight line increases its speed uniformly from 30 m/s to 60 m/s over a time interval 1-min. The distance travelled during this time interval is

900 m

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1800 m

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2700 m

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3600 m

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Solution

The correct option is B 2700 m
Here, $a = \frac{v - u}{t} = \frac{60 - 30}{60} = 0.5 m / s^{2}$
and $s = \frac{v^{2} - u^{2}}{2 a} = \frac{{(60)}^{2} - {(30)}^{2}}{2 \times 0.5}$
$= 2700 m$

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A truck running along a straight line increases its speed uniformly from 30 m/s to 60 m/s over a time interval 1-min. The distance travelled during this time interval is

The correct option is B 2700 mHere, a=v−ut=60−3060=0.5m/s2and s=v2−u22a=(60)2−(30)22×0.5=2700m

The correct option is B 2700 m
Here, $a = \frac{v - u}{t} = \frac{60 - 30}{60} = 0.5 m / s^{2}$
and $s = \frac{v^{2} - u^{2}}{2 a} = \frac{{(60)}^{2} - {(30)}^{2}}{2 \times 0.5}$
$= 2700 m$