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Question
A truck travelling due north at 50 km/hr turns west and travels at the same speed. What is the change in velocity?
A truck travelling due north at 50 km/hr turns west and travels at the same speed. What is the change in velocity?
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Solution
The correct option is D 50√2 km/hr south-west
Initial velocity of truck,
V1=50^j
Final velocity of truck,
V2=−50^i
Change in velocity = final velocity - initial velocity
ΔV=−50^i−50^j
Hence, magnitude of change in velocity is,
|−−→ΔV|=√(−50)2+(−50)2=50√2 km/hr
We can see that both component of resultant vector is negative, so the angle of change in velocity vector lies in third quadrant and equal to 45∘ from both west and south. Hence, the direction is South – West.
Initial velocity of truck,
V1=50^j
Final velocity of truck,
V2=−50^i
Change in velocity = final velocity - initial velocity
ΔV=−50^i−50^j
Hence, magnitude of change in velocity is,
|−−→ΔV|=√(−50)2+(−50)2=50√2 km/hr
We can see that both component of resultant vector is negative, so the angle of change in velocity vector lies in third quadrant and equal to 45∘ from both west and south. Hence, the direction is South – West.
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