You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Boyle's Law

A tube 1 cm...

Question

A tube $1 c m^{2}$ in cross section is attached to the top of a vessel $1 c m$ high and of cross section $100 c m^{2}$ . Water is poured into the system filling it to a depth of $100 c m$ above the bottom of the vessel as shown in the figure. Take $g = 10 m s^{- 2}$ . Find the correct statement.

The force exerted by water against the bottom of the vessel is

100 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

The weight of water in the system is

1.99 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Both (a) and (b) are correct

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Neither (a) nor (b) is correct

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D Both (a) and (b) are correct
$P = 100 c m \times 1 g c m^{- 3} \times 1000 c m s^{- 2} = 10^{5} d y n e - c m^{- 2}$
$F = 10^{5} \times 100 d y n e = 100 N$
Again, $V = 199 c m^{3}$
Weight $= 199 \times 1 \times 1000 d y n e = 1.99 N$

Suggest Corrections

Similar questions

Q. A tube

1 {cm}^{2}

in cross section is attached to the top of a vessel

1 cm

high and of cross section

100 {cm}^{2}

. Water is poured into the system filling it upto a height of

100 cm

above the bottom of the vessel as shown in the figure. Take

g = 10 {m/s}^{2}

. Find the correct statement. Take atmospheric pressure

P_{0} = 10^{5} bar

Q. A tube

1 {cm}^{2}

in cross section is attached to the top of a vessel

1 cm

high and of cross section

100 {cm}^{2}

. Water is poured into the system filling it upto a height of

100 cm

above the bottom of the vessel as shown in the figure. Take

g = 10 {m/s}^{2}

. Find the correct statement. Take atmospheric pressure

P_{0} = 10^{5} bar

Q. A cylindrical vessel open at the top is

20 c m

high and

10 c m

in diameter. A circular hole whose cross-sectional is area

1 {cm}^{2}

is cut at the centre of the bottom of the vessel. Water flows from a tube above it into the vessel at the rate

100 {cm}^{3} s^{- 1}

. The height of water (in

c m

) in the vessel under steady state is (Take

{g = 1000 cm s}^{- 2})

Q. A cylindrical vessel open at the top is

20 c m

high and

10 c m

in diameter. A circular hole whose cross-sectional area

1 {c m}^{2}

is cut at the centre of the bottom of the vessel. Water flows from a tube above it into the vessel at the rate

100 {c m}^{3} s^{- 1}

. The height of water in the vessel under steady state (in cm) is

Q. Water is being poured into a vessel at a constant rate

q m^{2} / s

. There is a small aperture of cross-section area 'a' at the bottom of the vessel. The maximum level of water in the vessel is proportional to:

Join BYJU'S Learning Program

A tube 1cm2 in cross section is attached to the top of a vessel 1cm high and of cross section 100cm2. Water is poured into the system filling it to a depth of 100cm above the bottom of the vessel as shown in the figure. Take g=10ms−2. Find the correct statement.

The correct option is D Both (a) and (b) are correctP=100cm×1gcm−3×1000cms−2=105dyne−cm−2F=105×100dyne=100NAgain, V=199cm3Weight =199×1×1000dyne=1.99N

A tube $1 c m^{2}$ in cross section is attached to the top of a vessel $1 c m$ high and of cross section $100 c m^{2}$ . Water is poured into the system filling it to a depth of $100 c m$ above the bottom of the vessel as shown in the figure. Take $g = 10 m s^{- 2}$ . Find the correct statement.

The correct option is D Both (a) and (b) are correct
$P = 100 c m \times 1 g c m^{- 3} \times 1000 c m s^{- 2} = 10^{5} d y n e - c m^{- 2}$
$F = 10^{5} \times 100 d y n e = 100 N$
Again, $V = 199 c m^{3}$
Weight $= 199 \times 1 \times 1000 d y n e = 1.99 N$