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Question

A tube closed at one end and containing air produces fundamental note of frequency of 256 Hz. If the tube is open at both ends, the fundamental frequency will be

A
512 Hz
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B
384 Hz
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C
128 Hz
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D
64 Hz
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Solution

The correct option is A 512 Hz
For closed organ pipe, frequency of the fundamental note
νoc=v4l, where v is velocity of sound and l is the

length of the pipe.
For open organ pipe, frequency of the fundamental note
νoo=v2l=2νoc=2×256=512 Hz

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