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Question

A tube contains a sample of hydrogen atoms which are all in their third excited state. The atoms de-excite and spectrum of radiation is emitted. The spectrum is shown in given figure. Line 6 corresponds to the highest frequency. Then,

A
The line 2 represents a transition from quantum state n = 3 to n = 2
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B
The line 5 represents the one with second smallest wavelength
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C
Line 1 belongs to Lyman series
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D
Line 3 belongs to balmer series
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Solution

The correct options are
A The line 2 represents a transition from quantum state n = 3 to n = 2
B The line 5 represents the one with second smallest wavelength
D Line 3 belongs to balmer series
By computing the energy differences between the sates, we can say lines 4, 5, and 6 belongs to Lyman series. Lines 2 and 3 are the first two lines of Balmer series and line 1 is the first line of Paschen series.

Line 2 belongs to Balmer series, and it represents the transition from n = 3 to n = 2 because it has the least energy released.

Line 5 has the second largest frequency, so it has the second smallest wavelength.

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