A tube well having a capacity of $4 m^{3}$ /hour operates for 20 hours each day during the irrigation season. How much area can be commanded if the irrigation interval is 20 days and depth of irrigation is 7 cm?

1.71 \times 10^{4} m^{2}

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1.14 \times 10^{4} m^{2}

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22.9 \times 10^{4} m^{2}

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2.29 \times 10^{4} m^{2}

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Solution

The correct option is D $2.29 \times 10^{4} m^{2}$
Discharge from tube well,
$Q = 4 m^{3} / h r$

Depth of irrigation,
$D = 7 c m$

Total time of operation,
$T = 20 \times 20 = 400 h o u r s$
$∴ Command Area = \frac{Q \times T}{D} = \frac{4 \times 400}{0.07}$

$= 2.28 \times 10^{4} m^{2}$

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A tube well having a capacity of 4 m3/hour operates for 20 hours each day during the irrigation season. How much area can be commanded if the irrigation interval is 20 days and depth of irrigation is 7 cm?

The correct option is D 2.29×104 m2Discharge from tube well, Q=4 m3/hr Depth of irrigation, D=7 cm Total time of operation, T=20×20=400 hours ∴ Command Area=Q×TD=4×4000.07 =2.28×104m2

A tube well having a capacity of $4 m^{3}$ /hour operates for 20 hours each day during the irrigation season. How much area can be commanded if the irrigation interval is 20 days and depth of irrigation is 7 cm?

The correct option is D $2.29 \times 10^{4} m^{2}$
Discharge from tube well,
$Q = 4 m^{3} / h r$

Depth of irrigation,
$D = 7 c m$

Total time of operation,
$T = 20 \times 20 = 400 h o u r s$
$∴ Command Area = \frac{Q \times T}{D} = \frac{4 \times 400}{0.07}$

$= 2.28 \times 10^{4} m^{2}$