Question

A tuning for of frequency $600Hz$ produces a progressive travelling wave having wave velocity $300m/s$. Two particles of a medium, separated by $1.5m$, vibrate being affected by the wave (A) in phase

• A. in same phase
• B. in opposite phase
• C. $45$ out of phase.
• D. none of these

Answer 1

The correct option is A in same phase

Wavelength of the wave $\lambda =\frac{v}{\nu }$
Given : $v=300m/s$ and $\nu =600Hz$
$⟹$ $\lambda =\frac{300}{600}=0.5m$
Thus, separation between two particles $d=1.5m=3\lambda$
Since, separation between two particles is equal to integral multiple of wavelength. This means the two particles are in same phase.