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Question

A tuning fork A of frequency 512Hz produces 5 beats per second when sounded with another tuning fork B of unknown frequency. If B is located with wax the number of beats is again 5 per second. The frequency of the tuning fork B before it was loaded is

A
502Hz
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B
507Hz
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C
517Hz
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D
522Hz
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Solution

The correct option is C 517Hz
Frequency of A , n=512Hz

Number of beats/sec, m=5

Frequency of B, n=512±5=517or505

On loading B, its frequency decreases from 517 to 505, so that number of beats per second remains 5.

Hence, frequency of B, when not loaded =517Hz

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