A tuning fork A when sounded with a tuning fork B of frequency 480Hz produces 5 beats per second. When the prongs of A are loaded with wax, it gives 3 beats per second. The original frequency of the tuning fork A is:
A
475Hz
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B
485Hz
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C
483Hz
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D
477Hz
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Solution
The correct option is B485Hz Given: fB=480Hz Beat frequency observed on sounding both forks is 5Hz ⇒fA=485Hz or 475Hz If the intial frequency of A is 475Hz and it reduces further due to waxing, the beat frequency will increase. (∵fB=480Hz)
However the beat frequency is decreasing to 3Hz, which is only possible if the initial frequency of the fork A is 485Hz Thus it is feasible to get 3 beats per second, when fA↓ to 483Hz after waxing. ∴fA=485Hz