A tuning fork A when sounded with another tuning fork B of frequency 612Hz produces 4 beats per second. When A filled , the number,the number of beats reduces to 1 per second . the frequency of A is
A
608Hz
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B
616Hz
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C
618Hz
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D
610Hz
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Solution
The correct option is A608Hz Let the frequency of A be fA. Beat frequency b=|fA−fB| ∴4=|fA−612| On filling the tuning fork, its frequency increases. Now, beats gets reduced to 1 when A is filled and sounded with B. This implies that frequency of A must be lower than that of B. Or 4=612−fA ⟹fA=612−4=608Hz