CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A tuning fork arrangement (pair) produces 4beats/s with one fork of frequency 288 cps. A little wax is placed on the unknown fork and it then produces 2 beats/s. The frequency of the unknown fork is-

A
286cps
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
292cps
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
294cps
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
288cps
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 292cps

An unknown tuning fork is producing 4beats/sec with the fork of frequency 288cps. This means that their frequencies differ by 4. The unknown fork might have frequency either 284cps or 292cps.

On the application of wax, the number of beats reduce to 2 per second which means they differ only by 2 and it is only possible when the unknown fork has a greater frequency.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Periodic Motion and Oscillation
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon