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Standard XII

Physics

Beat Frequency

A tuning fork...

Question

A tuning fork having unknown frequency is sounded together with another tuning fork B of frequency $512 H_{Z}$ 4 beats are heard. Now the tuning fork A is loaded with a little wax. The two forks are again sounded together. Now 5 beats are heard. What is the frequency of A?

506 Hz

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507 Hz

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508 Hz

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509 Hz

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Solution

The correct option is C 508 Hz
Since 4 beats are heard with B,
A may have frequency $512 + 4 = 416 H_{Z} o r 512 - 4 = 508 H_{Z}$
Since 5 beats are heard after applying wax on A which is greater than 4
A’s frequency should be $508 H_{Z}$

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Similar questions

Q. A tuning fork having unknown frequency is sounded together with another tuning fork B of frequency

512 H_{Z}

4 beats are heard. Now the tuning fork A is loaded with a little wax. The two forks are again sounded together. Now 5 beats are heard. What is the frequency of A?

Q. When two tuning forks, fork

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A tuning fork having unknown frequency is sounded together with another tuning fork B of frequency 512HZ 4 beats are heard. Now the tuning fork A is loaded with a little wax. The two forks are again sounded together. Now 5 beats are heard. What is the frequency of A?

The correct option is C 508 HzSince 4 beats are heard with B, A may have frequency 512+4=416 HZ or 512−4=508 HZ Since 5 beats are heard after applying wax on A which is greater than 4 A’s frequency should be 508HZ

A tuning fork having unknown frequency is sounded together with another tuning fork B of frequency $512 H_{Z}$ 4 beats are heard. Now the tuning fork A is loaded with a little wax. The two forks are again sounded together. Now 5 beats are heard. What is the frequency of A?

The correct option is C 508 Hz
Since 4 beats are heard with B,
A may have frequency $512 + 4 = 416 H_{Z} o r 512 - 4 = 508 H_{Z}$
Since 5 beats are heard after applying wax on A which is greater than 4
A’s frequency should be $508 H_{Z}$